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Question -

At 450 K, Kp= 2.0 × 1010/bar for the givenreaction at equilibrium.

What is Kat this temperature?



Answer -

Forthe given reaction,

Δn = 2 – 3 = – 1

T = 450 K

R = 0.0831 bar L bar K–1 mol–1

 = 2.0 × 1010 bar –1

Weknow that,

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