Question -
Answer -
(i) Since n =3, the element belongs to the 3rd period.It is a p–blockelement since the last electron occupies the p–orbital.
There are four electrons in the p–orbital. Thus, thecorresponding group of the element
= Number of s–block groups + number of d–blockgroups + number of p–electrons
= 2 + 10 +4
= 16
Therefore, the element belongs to the 3rd period and 16th groupof the periodic table. Hence, the element is Sulphur.
(ii) Since n =4, the element belongs to the 4th period.It is a d–blockelement as d–orbitalsare incompletely filled.
There are 2 electrons in the d–orbital.
Thus, thecorresponding group of the element
= Number of s–block groups + number of d–blockgroups
= 2 + 2
= 4
Therefore, it is a 4th periodand 4th group element. Hence, the element is Titanium.
(iii) Since n =6, the element is present in the 6th period.It is an f –blockelement as the last electron occupies the f–orbital. It belongs to group 3of the periodic table since all f-block elements belong to group3. Its electronic configuration is [Xe] 4f7 5d1 6s2. Thus, its atomic number is 54 + 7 + 2 + 1 = 64. Hence,the element is Gadolinium.