MENU
Question -

A student forgot to add the reaction mixture to theround bottomed flask at 27┬░C but put it on the flame. After a lapse of time, herealised his mistake. By using a pyrometer, he found that the temperature ofthe flask was 477┬░C. What fraction of air would have been expelled out ?



Answer -

Sincethe student was working in the laboratory, there is no change in pressure.Thus, CharlesтАЩ Law is applicable.
According to given data : V1┬а=V L (say) V2┬а= ?
T1┬а= 27+273 =300 K; T2┬а= 477 + 273 =750K
T1┬а=┬аT2┬аorV2┬а=┬аT1┬а=\frac { (VL)\times (750K) }{ 300K } = 2.5 VL
Thus, volume of air expelled = 2.5 V тАУ V = 1.5 V 1.5V
Fraction of air expelled =┬а1.5V┬а=┬а3┬а.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×