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Question -

A student forgot to add the reaction mixture to theround bottomed flask at 27°C but put it on the flame. After a lapse of time, herealised his mistake. By using a pyrometer, he found that the temperature ofthe flask was 477°C. What fraction of air would have been expelled out ?



Answer -

Sincethe student was working in the laboratory, there is no change in pressure.Thus, Charles’ Law is applicable.
According to given data : V1 =V L (say) V2 = ?
T1 = 27+273 =300 K; T2 = 477 + 273 =750K
T1 = T2 orV2 = T1 =\frac { (VL)\times (750K) }{ 300K } = 2.5 VL
Thus, volume of air expelled = 2.5 V – V = 1.5 V 1.5V
Fraction of air expelled = 1.5V = 3 .

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