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Question -

34.05 mL of phosphorus vapours weigh 0-0625 g at546°C and 1.0 bar pressure. What is the molar mass of phosphorus ?



Answer -

According to ideal gas equation,
PV = n RT ; PV = 
M orM = PV
Accordingto available data :
Mass of phosphorus vapours (W) = 0.0625 g
Volume of vapours (V) = 34.05 mL = 34.05 × 103 L
Pressure of vapours (P) = 1.0 bar.
Gas constant (R) = 0.083 bar L K-1 mol-1
Temperature (T) = 546 + 273 = 819 K

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