The Total solution for NCERT class 6-12
The angles of a triangle are (x − 40)0, (x − 20) 0 and(1/2 x − 10) 0. Find the value of x.
The angles of atriangle are (x − 40)0, (x − 20) 0 and (1/2 x −10) 0
Sum of all angles oftriangle = 1800
(x − 40)0 +(x − 20) 0 + (1/2 x − 10) 0 = 1800
5/2 x – 700 =1800
5/2 x = 1800 +700
5x = 2(250) 0
x = 5000/5
x = 1000