Question -
Answer -
Let’s assume the G.P.to be a, ar, ar2, ar3,…
Then according to thequestion, we have
a + ar + ar2 =16 and ar3 + ar4 + ar5 =128
a (1 + r + r2)= 16 … (1) and,
ar3(1 + r + r2) = 128 … (2)
Dividing equation (2)by (1), we get
r3 = 8
r = 2
Now, using r = 2 in(1), we get
a (1 + 2 + 4) = 16
a (7) = 16
a = 16/7
Now, the sum of termsis given as
