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Question -

How many terms of G.P. 3, 32, 33, … are needed togive the sum 120?



Answer -

Given G.P. is 3, 32,33, …

Let’s considerthat n terms of this G.P. be required to obtain the sum of120.

We know that,

Here, a =3 and r = 3

Equating the exponentswe get, n = 4

Therefore, four termsof the given G.P. are required to obtain the sum as 120.

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