Question -
Answer -
Let F (x, y)be the curve and let (x, y) be a point on the curve. Theslope of the tangent to the curve at (x, y) is 
According to the given information:
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This is a linear differential equation of the form:
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The general equation of the curve is given by therelation,
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Therefore, equation (1) becomes:
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The curve passes through point (0, 2).
Therefore, equation (2) becomes:
0 + 2 – 4 = Ce0
⇒ – 2 = C
⇒ C = – 2
Substituting C = –2 in equation (2), we get:
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This is the required equation of the curve.