The Total solution for NCERT class 6-12
Admission fee andbooks etc. = ₹ 1800First month’s savings = ₹ 50Increase in monthly savings = ₹ 720Period = 1 year = 12 monthsHere a = 50, d = 20 and n = 12S12 = n/2 [2a + (n – 1) d]= (12/2) [2 x 50 + (12 –1) x 20]= 6[100 + 11 x 20]= 6[100 + 220]= 6 x 320 = ₹ 1920Savings = ₹ 1920Yes, she will be able to send her daughter.