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Question -

A man saved ₹ 16500 in ten years. In each year after the first he saved ₹ 100 more than he did in the preceding year. How much did he save in the first year ?



Answer -

Savings in 10 years =₹ 16500
S10 = ₹ 16500 and d = 7100
Sn = n/2 [2a + (n – 1)d]
16500= 10/2 [2 x a + (10 –1) x 100]
16500 = 5 (2a + 900)
16500 = 10a + 4500
=> 10a = 16500 – 4500 = 12000
a = 1200
Saving for the first year = ₹ 1200

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