Question -
Answer -
Let the four terms of an A.P. be (a – 3d), (a – d), (a + d) and (a + 3d)
Now according to the condition,
Sum of these terms = 50
=> (a – 3d) + (a – d) + (a + d) + (a + 3d) = 50
=> a – 3d + a – d + a + d + a – 3d= 50
=> 4a = 50
=> a = 25/2
and greatest number = 4 x least number
=> a + 3d = 4 (a – 3d)
=> a + 3d = 4a – 12d
=> 4a – a = 3d + 12d