The Total solution for NCERT class 6-12
an = a + nbLet n= 1, 2, 3, 4, 5, тАжтАжтАж.a1┬а= a + ba2┬а= a + 2ba3┬а= a + 3ba4┬а= a + 4ba5┬а= a + 5bWe see that it is an A.P. whose common difference is b and a for any real valueof a and bas a2┬атАУ a1┬а= a + 2b тАУ a тАУ b = ba3┬атАУ a2┬а= a + 3b тАУ a тАУ 2b = ba4┬атАУ a3┬а= a + 4b тАУ a тАУ 3b = band a5┬атАУ a4┬а= a + 5b тАУ a тАУ 4b = b