Question -
Answer -
Since ╬ФABQ and ╬ФPBQ lie onthe same base BQ and are between the same parallels AP and BQ,
тИ┤Area (╬ФABQ) = Area (╬ФPBQ) тАж (1)
Again, ╬ФBCQ and ╬ФBRQ lieon the same base BQ and are between the same parallels BQ and CR.
тИ┤Area (╬ФBCQ) = Area (╬ФBRQ) тАж (2)
On adding equations (1)and (2), we obtain
Area (╬ФABQ) + Area (╬ФBCQ)= Area (╬ФPBQ) + Area (╬ФBRQ)
тЗТ Area (╬ФAQC) = Area (╬ФPBR)