Question -
Answer -
Since ΔABQ and ΔPBQ lie onthe same base BQ and are between the same parallels AP and BQ,
∴Area (ΔABQ) = Area (ΔPBQ) … (1)
Again, ΔBCQ and ΔBRQ lieon the same base BQ and are between the same parallels BQ and CR.
∴Area (ΔBCQ) = Area (ΔBRQ) … (2)
On adding equations (1)and (2), we obtain
Area (ΔABQ) + Area (ΔBCQ)= Area (ΔPBQ) + Area (ΔBRQ)
⇒ Area (ΔAQC) = Area (ΔPBR)