The Total solution for NCERT class 6-12
In the given figure, ABCDEis a pentagon. A line through B parallel to AC meets DC produced at F. Showthat
(i) ar (ACB) = ar (ACF)
(i) ΔACB and ΔACF lie onthe same base AC and are between
The same parallels AC andBF.
∴Area (ΔACB) = Area (ΔACF)
(ii) It can be observedthat
Area (ΔACB) = Area (ΔACF)
⇒Area (ΔACB) + Area (ACDE) = Area (ACF) + Area (ACDE)
⇒ Area (ABCDE) = Area (AEDF)