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Question -

DiagonalsAC and BD of a trapezium ABCD with AB || DC intersect each other at O. Provethat ar (AOD) = ar (BOC).




Answer -

It can be observed thatΔDAC and ΔDBC lie on the same base DC and between the same parallels AB and CD.

Area (ΔDAC) = Area (ΔDBC)

Area (ΔDAC) − Area (ΔDOC) = Area (ΔDBC) − Area (ΔDOC)

Area (ΔAOD) = Area (ΔBOC)

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