The Total solution for NCERT class 6-12
(i) x + y –z = 32x + 3y + z = 103x – y – 7z = 1
(ii) x + y + z = 3
2x – y + z = -1
2x + y – 3z = -9
(iii) 6x – 12y + 25z = 4
4x + 15y – 20z = 3
2x + 18y + 15z = 10
(iv) 3x + 4y + 7z = 14
2x – y + 3z = 4
x + 2y – 3z = 0
(v) (2/x) – (3/y) + (3/z) = 10
(1/x) + (1/y) + (1/z) = 10
(3/x) – (1/y) + (2/z) = 13
(vi) 5x + 3y + z = 16
2x + y + 3z = 19
x + 2y + 4z = 25
(vii) 3x + 4y + 2z = 8
2y – 3z = 3
x – 2y + 6z = -2
(viii) 2x + y + z = 2
x + 3y – z = 5
3x + y – 2z = 6
(ix) 2x + 6y = 2
3x – z = -8
2x – y + z = -3
(x) 2y – z = 1
x – y + z = 2
2x – y = 0
(xi) 8x + 4y + 3z = 18
2x + y + z = 5
x + 2y + z = 5
(xii) x + y + z = 6
x + 2z = 7
3x + y + z = 12
(xiii) (2/x) + (3/y) + (10/z) = 4,
(4/x) – (6/y) + (5/z) = 1,
(6/x) + (9/y) – (20/z) = 2, x, y, z ≠ 0
(xiv) x – y + 2z = 7
3x + 4y – 5z = -5
2x – y + 3z = 12
(i)