The Total solution for NCERT class 6-12
ABCD is arhombus. Show that diagonal AC bisects тИаA as well as тИаC and diagonal BD bisects тИаB as well as тИаD.
Given that,
ABCD is a rhombus.
AC and BD are its diagonals.
Proof,
AD = CD (Sides of a rhombus)
тИаDAC = тИаDCA (Angles opposite of equal sides of atriangle are equal.)
also, AB || CD
тЗТтИаDAC = тИаBCA (Alternate interior angles)
тЗТтИаDCA = тИаBCA
, AC bisects тИаC.
Similarly,
We can prove that diagonal AC bisects тИаA.
Following the same method,