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Question -

A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km/hr more, it would have taken 30 minutes less for the journey. Find the original speed of the train. [CBSE 2006C]



Answer -

Distance to be covered = 90 km
Let uniform-original speed = x km/h
Increased speed = (x + 15) km/hr
According to the condition,
┬а
=> x2 + 60x тАУ 45x тАУ 2700 = 0
=> x (x + 60) тАУ 45 (x + 60) = 0
=> (x + 60)(x тАУ 45) = 0
Either x + 60 = 0, then x = -60 which is not possible being negative
or x тАУ 45 = 0, then x = 45
Original speed of the train = 45 km/hr

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