Question -
Answer -
Side of the first square = x cm
Its area = (side)2 = x┬▓ cm2
Side of the second square = (x + 4) cm
Its area = (x + 4)2 cm2
According to the condition,
x┬▓ + (x + 4)2 = 656
=> x┬▓ + x┬▓ + 8x + 16 = 656
=> 2x┬▓ + 8x + 16 тАУ 656 = 0
=> 2x┬▓ + 8x тАУ 640 = 0
=> x┬▓ + 4x тАУ 320 = 0 (Dividing by 2)
=> x┬▓ + 20x тАУ 16x тАУ 320 = 0
=> x (x + 20) тАУ 16 (x + 20) = 0
=> (x + 20) (x тАУ 16) = 0
Either x + 20 = 0, then x = -20 Which is not possible being negative
or x тАУ 16 = 0, then x = 16
Side of the first square = 16 cm
and side of the second square = 16 + 4 = 20 cm