The Total solution for NCERT class 6-12
Let the base of a right triangle = xIts height = x тАУ 7and hypotenuse = 13 cm=> By Pythagoras Theorem(Hypotenuse)2┬а= (Base)2┬а+ (Height)2(13 )2┬а= x2┬а+(x тАУ 7)2=> 169 = x2┬а+ x2┬атАУ 14x + 49=> 2x2┬атАУ 14x + 49 тАУ 169 = 0=> 2x2┬атАУ 14x тАУ 120 = 0=> x2┬атАУ 7x тАУ 60 = 0 (Dividing by2)Hence required quadratic equation will be x2┬атАУ7x тАУ 60 = 0