Question -
Answer -
Let pipe of larger diameter can fill the tank = x hrs
and pipe of smaller diameter can fill in = y hrs
┬а
=> 26x + 80 = x┬▓ + 10x
=> x┬▓ + 10x тАУ 26x тАУ 80 = 0
=> x┬▓ тАУ 16x тАУ 80 = 0
=> x┬▓ тАУ 20x + 4x тАУ 80 = 0
=> x (x тАУ 20) + 4 (x тАУ 20) = 0
=> (x тАУ 20) (x + 4) = 0
Either x тАУ 20 = 0, then x = 20
or x + 4 = 0, then x = тАУ 4 which is not possible
x = 20 and y = 10 + x = 10 + 20 = 30
Larger pipe can fill the tank in 20 hours and smaller pipe can fill in 30 hours.