MENU
Question -

In figure, AB || CD|| EF and GH || KL. Find HKL.



Answer -

Extend LK to meet line GF at point P.

From figure, CD || GF, so, alternate angles are equal.

CHG =HGP = 60°

HGP =KPF = 60° [Corresponding angles of parallellines are equal]

Hence, KPG=180 – 60 = 120°

=> GPK = AKL= 120° [Corresponding angles of parallellines are equal]

AKH = KHD = 25° [alternate angles of parallellines]

Therefore, HKL = AKH + AKL = 25 + 120 = 145°

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×