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Question -

In figure, rays OA,OB, OC, OD and OE have the common end point 0. Show that AOB+BOC+COD+DOE+EOA=360°.



Answer -

Given: Rays OA, OB, OC, OD and OE have the common endpoint O.

Draw an opposite ray OX to ray OA, which make a straight lineAX.

From figure:

AOB andBOX arelinear pair angles, therefore,

AOB +BOX = 1800

Or, AOB + BOC + COX = 1800 —–—–(1)

Also,

AOE andEOX arelinear pair angles, therefore,

AOE+EOX =180°

Or, AOE + DOE + DOX = 1800 —–(2)

By adding equations, (1) and (2), we get;

AOB + BOC + COF + AOE + DOE + DOX = 1800 + 1800

AOB + BOC + COD + DOE + EOA = 3600

Hence Proved.

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