The Total solution for NCERT class 6-12
Smaller area enclosed bythe circle x2 + y2 = 4and the line x + y = 2 is
A. 2 (π – 2)
B. π – 2
C. 2π – 1
D. 2 (π + 2)
The smaller areaenclosed by the circle, x2 + y2 =4, and the line, x + y = 2, is represented bythe shaded area ACBA as
Thus, the correct answeris B.
It can be observed that,
Area ACBA = Area OACBO –Area (ΔOAB)