Question -
Answer -
The area bounded by thecurves, (x – 1)2 + y2 =1 and x2 + y 2 =1, is represented by the shaded area as
On solving theequations, (x – 1)2 + y2 =1 and x2 + y 2 =1, we obtain the point of intersection as Aand B.
It can be observed thatthe required area is symmetrical about x-axis.
∴ Area OBCAO = 2 × AreaOCAO
We join AB, whichintersects OC at M, such that AM is perpendicular to OC.
The coordinates of Mare .
Therefore, required areaOBCAO = units