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Question -

सर्वसमिका का प्रयोग कर (4x + 2y) (4x – 2y) का मान ज्ञात कीजिए, उत्तर की जाँच कीजिए, यदि x = 2,y = 1.



Answer -

(4x + 2y) (4x – 2y)
= (4x)2 – (2y)2
= 16x2 – 4y2
उत्तर की जाँच : यदि x = 2, y = 1 तो

L.H.S. (4x + 2y) (4x – 2y)
= (4 × 2 + 2 × 1) (4 × 2 – 2 × 1)
= (8 + 2) (8 – 2) = 10 × 6 = 60

R.H.S. 16x2 – 4y2
= 16 (2)2 – 4 (1)2
= 64 – 4 = 60

⇒ L.H.S. = R.H.S.

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