The Total solution for NCERT class 6-12
(i) 2x (3x+ 5y) – 5y (2x – 3y)हल :2x (3x + 5y) – 5y × (2x – 3y)= 6x2 + 10xy – 10xy + 15y2 =6x2 + 15y2
(ii) x (y – z) + 2y (z-x) + z (x -y)हल :x × (y – z) + 2y × (z – x) + z × (x – y)= xy – xz + 2yz – 2xy + xz – yz = -xy + yz
(iii) y2 (y2 +1)– y3 (y +1) + y (y2 –y)हल :y2 × (y2 +1)– y3 × (y +1) + y × (y2 –y)= y4 +y2 – y4 – y3 +y3 – y2 = 0
(iv) x (1+x2) – x2 –(x – 1) – (x +x2)हल :x (1+x2) – x2 ×(x – 1) – (x +x2)= x + x3 – x3 + x2 –x – x2 = 0