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Question -

ABCis a triangle. Locate a point in the interior of ╬ФABC which is equidistant fromall the vertices of ╬ФABC.



Answer -

Circumcentreof a triangle is always equidistant from all the vertices of that triangle.Circumcentre is the point where perpendicular bisectors of all the sides of thetriangle meet together.

In╬ФABC, we can find the circumcentre by drawing the perpendicular bisectors ofsides AB, BC, and CA of this triangle. O is the point where these bisectors aremeeting together. Therefore, O is the point which is equidistant from all thevertices of ╬ФABC.

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