The Total solution for NCERT class 6-12
Inthe given figure, ∠B < ∠A and ∠C< ∠D. Show that AD < BC.
InΔAOB,
∠B < ∠A
⇒ AO < BO (Side opposite to smaller angleis smaller) … (1)
InΔCOD,
∠C < ∠D
⇒ OD < OC (Side opposite to smaller angleis smaller) … (2)
Onadding equations (1) and (2), we obtain
AO+ OD < BO + OC