The Total solution for NCERT class 6-12
ABC is an isosceles triangle with AB = AC.Drawn AP ⊥ BC to show that ∠B = ∠C.
In ΔAPB and ΔAPC,
∠APB = ∠APC (Each 90º)
AB =AC (Given)
AP = AP (Common)
∴ ΔAPB ≅ ΔAPC (Using RHS congruence rule)
⇒ ∠B = ∠C (By using CPCT)