The Total solution for NCERT class 6-12
x = 1, y = 6 is a solution of the equation8x – ay + a2 = 0Substituting the value of x and y,8 x 1-a x 6 + a2 = o⇒ 8 – 6a + a2 = 0⇒ a2 – 6a + 8 = 0⇒ a2 – 2a -4a + 8 = 0⇒ a (a – 2) – 4 (a – 2) = 0⇒ (a – 2) (a – 4) = 0Either a – 2 = 0, then a = 2or a – 4 = 0, then a = 4Hence a = 2, 4