The Total solution for NCERT class 6-12
Answer - 11 : -
As sin2 (−x)= (sin (−x))2 = (−sin x)2 =sin2x, therefore, sin2x is an evenfunction.
Answer - 12 : -
Adding (1) and (2), weobtain
Answer - 13 : -
As sin7 (−x)= (sin (−x))7 = (−sin x)7 =−sin7x, therefore, sin2x is an oddfunction.
It is known that, if f(x) is an oddfunction, then
Answer - 14 : -
It is known that,
Answer - 15 : -
Answer - 16 : -
sin (π − x) =sin x
Adding (4) and (5), weobtain
Let 2x = t ⇒ 2dx = dt
When x =0, t = 0
Answer - 17 : -
Answer - 18 : -
It can be seen that, (x −1) ≤ 0 when 0 ≤ x ≤ 1 and (x − 1) ≥ 0 when 1≤ x ≤ 4
Answer - 19 : -
A. 0
B. 2
C. π
D. 1
Answer - 20 : -
Hence, the correct answeris C.