The Total solution for NCERT class 6-12
Find the values of yfor which the distance between the points P (2, – 3) and Q (10, y) is 10 units.
Given: Distance between (2, – 3) and (10, y)is 10.
Using distance formula,
Simplify the above equation and find the valueof y.
Squaring both sides,
64 +(y+3)2 = 100
(y+3)2 = 36
y + 3 = ±6
y + 3 = +6 or y + 3 = −6
Therefore, y = 3 or -9.