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Question -

You have to show that∆AMP ∆AMQ. In thefallowing proof, supply the missing reasons.

Steps

Reasons

(i) PM = QM

(i)

(ii) PMA – QMA

(ii)

(iii) AM = AM

(iii)

(iv) ∆AMP = ∆AMQ

(iv)



Answer -

Steps

Reasons

(i) PM = QM

(i) Given

(ii) PMA = QMA

(ii) Given

(iii) AM = AM

(iii) Common

(iv) ∆AMP = ∆AMQ

(iv) SAS rule

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