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RD Chapter 6 Trigonometric Identities Ex 6.1 Solutions

Question - 71 : -

Answer - 71 : -

Question - 72 : - sec4 A (1 – sin4 A)– 2tan2 A = 1

Answer - 72 : -


Question - 73 : -

Answer - 73 : -


Question - 74 : -

Answer - 74 : -


Question - 75 : -

Answer - 75 : -


Question - 76 : - If cosec θ – sin θ = a3, sec θ –cos θ = b3, prove that a2b2 (a2 +b2) = 1

Answer - 76 : -


Question - 77 : -

Answer - 77 : -


Question - 78 : -

Answer - 78 : -


Question - 79 : - If a cos θ + b sin θ = m and a sin θ – b cos θ= n, prove that a2 + b2 = m2 +n2 

Answer - 79 : -


Question - 80 : - If cos A + cos2 A = 1, provethat sin2 A + sin4 A = 1

Answer - 80 : -

cos A + cos2 A= 1
⇒ cos A = 1 – cos2 A
⇒cos A = sin2 A
Now, sin2 A + sin4 A = sin2 A +(sin2 A)2
= cos A + cos2 A = 1 = R.H.S.

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