Question -
Answer -
Given, Two poles of heights 6 m and 11 m standon a plane ground.
And distance between the feet of the poles is12 m.
Let AB and CD be the poles of height 6m and11m.
Therefore, CP = 11 – 6 = 5m
From the figure, it can be observed that AP = 12m
By Pythagoras theorem for ΔAPC, we get,
AP2 = PC2 +AC2
(12m)2 + (5m)2 = (AC)2
AC2 = (144+25) m2 = 169 m2
AC = 13m
Therefore, the distance between their tops is 13 m.