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Question -

ABC is an isoscelestriangle with AC = BC. If AB2 = 2AC2, provethat ABC is a right triangle.



Answer -

Given, ΔABC is an isosceles triangle having AC= BC and AB2 = 2AC2

In ΔACB,

AC = BC

AB2 = 2AC2 

AB2 = AC+ AC2

        = AC2 +BC[Since, AC = BC]

Hence, by Pythagoras theorem ΔABC isright angle triangle.

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