The Total solution for NCERT class 6-12
In the fig.6.36,QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR.
Solution:
In ΔPQR,
∠PQR = ∠PRQ∴ PQ = PR ………………………(i)Given,
QR/QS = QT/PRUsing equation (i), we get
QR/QS = QT/QP……………….(ii)
In ΔPQS and ΔTQR, by equation (ii),
QR/QS = QT/QP∠Q = ∠Q∴ ΔPQS ~ ΔTQR [By SAS similarity criterion]