The Total solution for NCERT class 6-12
In the fig.6.36,QR/QS = QT/PR and тИа1 = тИа2. Show that ╬ФPQS ~ ╬ФTQR.
Solution:
In ╬ФPQR,
тИаPQR = тИаPRQтИ┤ PQ = PR тАжтАжтАжтАжтАжтАжтАжтАжтАж(i)Given,
QR/QS = QT/PRUsing equation (i), we get
QR/QS = QT/QPтАжтАжтАжтАжтАжтАж.(ii)
In ╬ФPQS and ╬ФTQR, by equation (ii),
QR/QS = QT/QPтИаQ = тИаQтИ┤ ╬ФPQS ~ ╬ФTQR [By SAS similarity criterion]