Question -
Answer -
LetABCD be a rhombus whose diagonals intersect each other at O such that AC = 16cm and BD = 30 cm
Since, the diagonals of a rhombus bisect each other at 90┬░.
тИ┤ OA =OC = 8 cm and OB = OD = 15 cm
In right тИЖOAB,
AB2┬а= OA2┬а+OB2┬а(By Pythagoras property)
= (8)2+ (15)2┬а=64 + 225
= 289
тИ┤ AB =
=┬а17 cm
Since AB = BC = CD = DA (Property of rhombus)
тИ┤Required perimeter of rhombus
= 4 ├Ч side = 4 ├Ч 17 = 68 cm.
┬а