Question -
Answer -
Let us assume x be the smaller of the two consecutive even positive integers
∴ Other integer = x + 2
It is also given in the question that, both the integers are larger than 5
∴ x > 5 ….(i)
Also, it is given in the question that the sum of two integers is less than 23.
∴ x + (x + 2) < 23
2x + 2 < 23
x < 21/2
x < 10.5 …. (ii)
Thus, from (i) and (ii) we have x is an even number and it can take values 6, 8 and 10
Hence, possible pairs are (6, 8), (8, 10) and (10, 12).