Question -
Answer -
Given that, 3 (2 тАУ x) тЙе 2 (1 тАУ x)
By multiplying we get
6 тАУ 3x тЙе 2 тАУ 2x
Now by adding 2x to both the sides,
6 тАУ 3x + 2x тЙе 2 тАУ 2x + 2x
6 тАУ x тЙе 2
Again by subtracting 6 from both the sides, we get
6 тАУ x тАУ 6 тЙе 2 тАУ 6
тАУ x тЙе тАУ 4
Multiplying throughout inequality by negative sign we get
x тЙд 4
тИ┤ The solutions of the given inequality are defined by all the real numbers greater than or equal to 4.
Hence the required solution set is (- тИЮ, 4]