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Question -

3 (1 тАУ x) < 2 (x + 4)



Answer -

Given,
3 (1 тАУ x) < 2 (x + 4)
Solving the given inequality, we get
3 (1 тАУ x) < 2 (x + 4)
Multiplying we get
= 3 тАУ 3x < 2x + 8
On rearranging we get
= 3 тАУ 8 < 2x + 3x
= тАУ 5 < 5x
Now by dividing 5 on both sides we get
-5/5 < 5x/5
= тАУ 1 < x
Now, the graphical representation of the solution is as follows:

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