The Total solution for NCERT class 6-12
f(x) = x4 – 2x3 + 3x2 –ax – bDividing f(x) by x – 1, the remainder = 6Now let x – 1 = 0, then x = 1∴ f(1) = (1)4 – 2(1)3 + 3(1)2 -ax1-b= 1 -2 + 3-a-b = 2-a-b∴Remainder = 6∴ 2 – a– b = 6 ⇒ a + b= 2 – 6 = -4Hence a + b = -4