The Total solution for NCERT class 6-12
f(x) = x4┬атАУ 2x3┬а+ 3x2┬атАУax тАУ bDividing f(x) by x тАУ 1, the remainder = 6Now let x тАУ 1 = 0, then x = 1тИ┤┬аf(1) = (1)4┬атАУ 2(1)3┬а+ 3(1)2┬а-ax1-b= 1 -2 + 3-a-b = 2-a-bтИ┤Remainder = 6тИ┤ 2 тАУ aтАУ b = 6┬а тЗТ a + b= 2 тАУ 6 = -4Hence a + b = -4