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Question -

Find the area of the triangle with vertices at the points:

(i) (3, 8), (-4, 2) and (5, -1)

(ii) (2, 7), (1, 1) and (10, 8)

(iii) (-1, -8), (-2, -3) and (3, 2)

(iv) (0, 0), (6, 0) and (4, 3)



Answer -

(i) Given (3, 8), (-4,2) and (5, -1) are the vertices of the triangle.

We know that, ifvertices of a triangle are (x1, y1), (x2, y2)and (x3, y3), then the area of the triangle is given by:

(ii) Given (2, 7), (1,1) and (10, 8) are the vertices of the triangle.

We know that ifvertices of a triangle are (x1, y1), (x2, y2)and (x3, y3), then the area of the triangle is given by:

(iii) Given (-1, -8),(-2, -3) and (3, 2) are the vertices of the triangle.

We know that ifvertices of a triangle are (x1, y1), (x2, y2)and (x3, y3), then the area of the triangle is given by:

As we know area cannotbe negative. Therefore, 15 square unit is the area

Thus area of triangleis 15 square units

(iv) Given (-1, -8),(-2, -3) and (3, 2) are the vertices of the triangle.

We know that ifvertices of a triangle are (x1, y1), (x2, y2)and (x3, y3), then the area of the triangle is given by:

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