Question -
Answer -
Let f(x) = 3x4 −8x3 + 12x2 − 48x +25.
Now,
gives x = 2 or x2+ 2= 0 for which there are no real roots.
Therefore, we consider only x =2 ∈[0, 3].
Now, we evaluate the value of f atcritical point x = 2 and at the end points of the interval [0,3].
Hence, we can conclude that the absolutemaximum value of f on [0, 3] is 25 occurring at x =0 and the absolute minimum value of f at [0, 3] is − 39occurring at x = 2.