The Total solution for NCERT class 6-12
If f (x) = 3x2 +15x + 5, then the approximate value of f (3.02) is
A. 47.66 B. 57.66 C. 67.66 D. 77.66
Let x = 3 and Δx =0.02. Then, we have:
Hence, the approximate value of f(3.02)is 77.66.
The correct answer is D.